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2023年安徽省合肥市第四十五中学中考模拟数学试题(含答案)
展开合肥市第四十五中学中考数学模拟试卷
一、选择题(本题共10小题,每小题4分,满分40分)
1.-2023的相反数是( )
A. B. C.-2023 D.2023
2.下面计算正确的是( )
A. B. C. D.
3.2023年3月5日,李克强总理代表国务院作《政府工作报告》.报告中指出,2022年我国经济结构和区域布局继续优化,粮食产量13700亿斤,创历史新高,把数据13700亿用科学记数法表示为( )
A. B. C. D.
4.如图所示的手提水果篮,其俯视图是( )
A. B. C. D.
5.如图是一款手推车的平面示意图,其中,,,则的度数为( )
A.56 B.66 C.98 D.104
6.在一次演讲比赛中,七位评委为某位选手打出的分数如下:87,95,89,99,87,93,97(单位:分).若去掉一个最高分和一个最低分,则去掉前与去掉后没有改变的一个统计量是( )
A.平均分 B.众数 C.中位数 D.方差
7.已知直线经过第一、二、三象限,且点在该直线上,设,则m的取值范围是( )
A. B. C. D.
8.如图,在平行四边形中,,,的平分线交的延长线于点E,交于点F,则等于( )
A.7∶4 B.7∶3 C.4∶3 D.4∶7
9.已知a,b,c为实数,且,,则a,b,c之间的大小关系是( )
A. B. C. D.
10.已知抛物线的图象如图所示,其对称轴为直线,那么一次函数的图象大致为( )
A | B | C | D |
二、填空题(本题共4小题,每小题5分,满分20分)
11.因式分解:______________.
12.如图,四边形内接于,是的直径,过点C作的切线交的延长线于点P,若,则______________.
13.如图,已知直角三角形中,,,将绕O点旋转至的位置,且为中点,在反比例函数上,则k的值______________.
14.如图,已知矩形中,,,点M,N分别在边,上,沿着折叠矩形,使点B,C分别落在,处,且点在线段上(不与两端点重合).
(1)若为线段的中点,则____________;
(2)折痕的长度的取值范围为_____________.
三、(本题共2小题,每小题8分,满分16分)
15.解不等式组:
16.如图,的顶点坐标分别为,,.将绕原点O逆时针旋转90°的图形得到.
(1)画出的图形,并写出的坐标.
(2)若点在边上,直接写出点P旋转后对应点的坐标.
四、(本题共2小题,每小题8分,满分16分)
17.甲工程队新建公路,每名工人每天工作8小时,则甲工程队每天可完成800米新建公路.乙工程队比甲工程队少15名工人,每名工人每天工作12小时,则乙工程队每天可完成600米新建公路,假定甲、乙两工程队的每名工人每小时完成的工作量相同,求乙工程队的工人有多少名?
18.观察以下等式:
第1个等式:,
第2个等式:,
第3个等式:,
……
按照以上规律,解决下列问题:
(1)按照此规律下去,第4个等式是:_______________________;
(2)写出你猜想的第n个等式(用含n的式子表示),并证明.
五、(本题共2小题,每小题10分,满分20分)
19.周末爬大蜀山,是合肥市民周末娱乐休闲、锻炼身体的方式之一.如图,某个周末小张同学从大蜀山西坡沿坡角为37°的山坡爬了280米,到达点E处,紧接着沿坡角为45°的山坡又爬了160米,到达山顶A处;请你计算大蜀山的高度.(结果精确到个位,参考数据:,,,,.)
20.学校即将开展红色经典诵读活动,李老师给学生推荐了3种不同的名著A,B,C.甲,乙两位同学分别从中任意选一种阅读,假设选任意一种都是等可能的.
(1)甲同学选中名著B的概率是
(2)请你利用画树状图或列表的方法,求甲、乙两位同学选中的名著不相同的概率.
六、(本题满分12分)
21.如图1,已知是的内接三角形,是的直径,是的弦,连接,交于点E.
(1)求证:;
(2)如图2,连接、,若,且,,求的长.
七、(本题满分12分)
22.已知:如图1,在中,,是的平分线,连接、,且于点D.
(1)求证:;
(2)如图2,点E、F分别是边、上的点,且于点E,求的值.
八、(本题满分14分)
23.如图,抛物线与x轴交于点A、B,与y轴交于点C,点A的坐标为,点B的坐标为.
(1)求抛物线的表达式;
(2)当时,抛物线有最小值5,求a的值;
(3)若点P是第四象限内抛物线上一动点,连接、,求的面积S的最大值.
参考答案
一、选择题(本题共10小题,每小题4分,满分40分)
1-5 DCDBA 6-10 CBBAD
二、填空题(本题共4小题,每小题5分,满分20分)
11. 12.40° 13. 14.(1) (2)
三、(本题共2小题,每小题8分,满分16分)
15.解:
··················································································3分
··················································································6分
∴原不等式组的解集为.································································8分
16.(1)如图所示,即为所求;
··················································································3分
··················································································5分
(2)··············································································8分
四、(本题共2小题,每小题8分,满分16分)
17.解:设乙工程队的工人有x名,
由题意得,··········································································4分
解得,
经检验,是原分式方程的解且符合题意,
答:乙工程队的工人有15名.·····························································8分
18.(1);··········································································3分
(2)第n个等式:
证明:
即·················································································8分
五、(本题共2小题,每小题10分,满分20分)
19.解:过点A作于D,过点E作于F,于G,则四边形为矩形,
∴,
在中,,
则(米),··········································································4分
在中,,
则(米),··········································································8分
∴(米),
答:大蜀山的高度约为281米.···························································10分
20.解:(1)∵共有3种不同的名著A,B,C,
∴其名著B的概率是:;································································3分
(2)根据题意画图(图略)
共有9中等可能的情况数,其中甲、乙两位同学选中的名著不相同的有9种,
则甲、乙两位同学选中的名著不相同的概率为:.············································10分
六、(本题满分12分)
21.(1),
弧弧,推出
∴·················································································5分
(2)·············································································12分
七、(本题满分12分)
22.(1)证明:∵证明:过点D作于点E,于点F,
可证
∴·················································································5分
或证A、C、B、D四点共圆
(2)可证,∵,∴为等腰直角三角形,
∵为等腰直角三角形
∴,∴,∴
∵,∴,∴
∴················································································12分
八、(本题满分14分)
23.(1)············································································4分
(2)或6···········································································9分
(2)的面积S的最大值································································14分
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