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    江苏省常州市部分学校2021-2022学年七年级上学期期中质量调研数学【试卷+答案】
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    江苏省常州市部分学校2021-2022学年七年级上学期期中质量调研数学【试卷+答案】

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    这是一份江苏省常州市部分学校2021-2022学年七年级上学期期中质量调研数学【试卷+答案】,共7页。

    2021~2022学年第一学期期中质量调研    2021.11

    注意事项:

    1本场考试时间为90分钟,全卷100分。

    2考生应将答案全部填写在答题卡相应位置上,答在本试卷上无效。

    一、选择题(本大题共8小题,每小题2分,共16分)

    1身份证号码32010619621118××××告诉我们很多信息,其中320106所属的省(直辖市、自治区)、市、县(县级市、区)的编码,19621118是出生的年、月、日;某人身份证号码是32110219810911××××,则此人出生的月份是(       

    A8 B10 C9 D11

    2.在数09,-0.18844.4332中,其中负有(   

    A2 B3 C4 D5

    3.下列各数:-103.144.112112112,其中无理数有   

    A1 B2 C3 D4

    4下列代数式中,单项式的是(  )

    A B C D

    5下列各组中的两项属于同类项的是(  )

    A B C D

    6下列计算正确的是(  )

    A                     B

    C                  D

    7如图,在数轴上有ab数,式子:① ,② ,③,④ ,⑤,⑥其中结果为正的式子有(   

    A1 B2 C3 D4

    8古希腊著名的毕达哥拉斯学派13610 … 这样的数称为三角形数,而把14916 … 这样的数称为正方形数 图中可以发现,任何一个大1正方形数都可以看作两个相邻三角形数之和.下列等式中,符合这一规律的是   

       A13 = 3+10      B25 = 9+16      C36 = 15+21     D49 = 18+31

     

    二、填空题(本大题共10小题,每小题2分,共20分)

    9若将向东行驶3km,记作3km向西行驶2km记作        

    10的倒数是      的相反数是      

    11单项式ab2c3数是     多项式2x33x1的次数      

    12.比较大小:           (填、或符号).

    13北京奥运会国家体育场“鸟巢”的建筑面积为258000平方米,那么258000平方米用科学记数法可表示为                   平方米

    14小明在电脑上每分钟录入汉字60个,小明的妈妈每分钟录入汉字50个,如果要录入汉字,那么妈妈比小明多用                      分钟

    15如图是计算机程序计算,若开始输入x=1,则最后输出的结果是        

    16.在数轴上,点A表示数-1AB两点之间的距离为3,则B表示数        

    17.若三个非零有理数abc满足,则       

    18已知在纸面上有一数轴,折叠纸面,数轴上-2表示点与7表示的点重合.若数轴上AB两点之间的距离为2021AB的左侧),且AB两点经以上方法折叠后重合,则A点表示的数是                 

    三、计算题(每小题4分,共16分)

    19.1                   2

     

     

    3                    4

     

     

     

     

     

    四、计算与化简(20题每小题5分,216分,共16分)

    20.1                         2

     

     

     

     

    21. 先化简,再求值:,其中

     

     

     

     

    五、解答题(本大题共4小题,226分,2324题各8分,2510分,共32分)

    22已知一个多项式的和是

    1)求这个多项式?

    2)若代数式的值是5,求这个多项式的值?

     

     

     

     

    23.有一批试剂,每瓶标准剂量为250毫升,现抽取8瓶样品进行检测,结果如下(单位:毫升):256248253260244255235242

    1 根据标准剂量,用正、负数记数填表;

    256

    248

    253

    260

    244

    255

    235

    242

    与标准的差距

     

     

     

     

     

     

     

     

    2)这8瓶样品试剂的总剂量是多少?

    3)若增加或者减少每瓶试剂剂量的人工费10/毫升,问8瓶样品试剂再加工制作成标准剂量需要多少人工费?

     

     

     

     

     

     

     

     

    24如图,用三种大小不同的六个正方形和一个缺角的长方形拼成大长方形ABCD其中 GH = 1 HM = 3BF= a.

    1)用含a的代数式表示CN=      cmDN=       cm.

    2)用含a的代数式表示大长方形ABCD的周长.

     

     

     

     

     

     

     

     

    25【阅读理解】 

    一般地,数轴上表示数m和数n的两点AB之间的距离等于mn两数差的绝对值,即AB=.例如,数轴上表示31的两点AB之间的距离是AB=;表示32两点CD之间的距离是CD=

    【知识运用】

    1)若数轴上表示数a的点位于42之间,求+的值;

     

     

    2)数轴上一点表示数a+=8,求a的值;

     

     

     

    3)如图, AB为数轴上两点,点 A所表示的数为20,点 B所表示的数为 40.现有一只电子蚂蚁 P从点 B出发,以 5个单位每秒的速度向左运动,设P 运动时间为t秒,  t为何值时, PA B三点中恰有某两点距离是另两点距离的两倍?

     

     

     

     

     


    2021学年第一学期期中质量调研七年级数学试卷参考答案

    一、   选择题(本大题共8小题,每小题2分,共16分)

    1C  2C  3A  4D  5D  6C  7B  8C

    二、   填空题(本大题共10小题,每小题2分,共20分)

    9-2km     10-3  3     11-1  3      12>  >     132.58×105  

    14    15-11     16-42     17-1    18-1008

    三、计算题(每小题4分,共16分)

    191=-10-4+8-3                ························ ························ ···············1 

    =-17+8                    ························ ························ ··············3

    =-9                       · ························ ············ ························ 4 

    2=2-2×2×2                ························ ························ ··············1

    =2-8                      ························ ························ ··············3

            =-6                       ························ ························ ··············4

       3=(1-5/6+1/4)×(-48)         ························ ························ ···············1

    =-48+5/6×48-1/4×48       ························ ························ ··············2

    =-48+40-12                ························ ························ ······· ·······3

    =-20                      ························ ························ ······ ········4

    4=-9×5-4÷4                 ························ ························ ······ ·······2

    =-45-1                     ························ ························ ······ ·······3

    =-46                       ························ ························ ···· ········4

    四、计算化简(第20题每小题5分,第216分共16分)

    20.(1=(-1+2-5)a                   ························ ························ ···········3  

    =-4a                        ························ ························ ··· ········5

       2=2x+2y-3x+3y                ························ ························ ···· ······3

            =-x+5y                      ························ ························ ···········5

    21      =3x2-7xy-2x2+6xy             ························ ························ ········2

    =x2-xy                       ························ ························ ··········4

       x2-xy = (-2)2-(-2)×1/2               ························ ························ ··········5

            =4+1                                                 =5                           ························ ·································6

    五、解答题(第226分,第2324题各8分,第2510分)

    22.(13b-2-(-2a-3b+1)               ························ ························ ···· ······1

    =3b-2+2a+3b-1                ························ ························ ··········2

    =2a+6b-3                     ························ ························ ··········3 

    2=2(a+3b)-3                   ························ ························ ·········4

    =2×5-3                       ························ ························ ········5

            =7                            ························ ································6

    231+6  -2  +3  +10  -6  +5  -15  -8        ························ ···················2

    2=250×8+(+6-2+3+10-6+5-15-8) 

    =2000-7

    =1993(毫升)                    ························ ································4

    答:                               ························ ·······························5

    3|+6|+|-2|+|+3|+|+10|+|-6|+|+5|+|-15|+|-8|

    =6+2+3+10+6+5+15+8

    =55(毫升)                      ························ ································6

    50×10=550(元)              ························ ························ ········7

    答:                              ························ ·································8

    241a+1   3a                       ························ ·······························2     

    2DC=CN+DN=a+1+3a=4a+1        ························ ·······························3

    BC=a×2+(a+1)×3=2a+3a+3=5a+3    ························ ······························4

    CABCD=(4a+1+5a+3)*2           ························ ··································6

    =18a+8                       ························ ··································8

    251 |a+4|+|a-2|=6                 ························ ····················· ·············2

       2(8-6) ÷2=1                   

            a=-4-1=-5                     ························ ··································3

    a=2+1=3                       ························ ································4

    34  6  8  18  24  36          ························ ·································10


     

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