高中数学2.4 平面向量的数量积当堂达标检测题

这是一份高中数学2.4 平面向量的数量积当堂达标检测题，共2页。试卷主要包含了在等腰中，，，则，已知三点等内容，欢迎下载使用。
2.4.2数量积的坐标表示、模、夹角 1、在等腰中，，，则(    )A．或        B．或      C．        D．2、定义向量的外积为，其中为与的夹角，若，则(    )A．                  B．               C．                D．3、点，动点满足，则点P的轨迹方程为     .                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                               4、已知，，若与的夹角为锐角，则的取值范围是       .5、已知三点、、.(1)证明：；(2)若点C使得四边形ABCD为矩形，求点C的坐标，并求该矩形对角线所夹的锐角的余弦值.     参考答案1.A 由，得，又，得，两式联立解得或，∴或，有或.2.D可得，而，∴，有.3. 由，得，即.4. 与的夹角为锐角，且，而，∴且，即且.5.(1)证明：可得，，，∴；(2)由(1)及四边形ABCD为矩形，得，设，则，∴，得，即；∴，得，，设与夹角为，则，∴该矩形对角线所夹的锐角的余弦值.